2sin^2x+5cosx=4

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Solution for 2sin^2x+5cosx=4 equation: 


Simplifying
2sin2x + 5cosx = 4

Reorder the terms:
5cosx + 2in2sx = 4

Solving
5cosx + 2in2sx = 4

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2in2sx' to each side of the equation.
5cosx + 2in2sx + -2in2sx = 4 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
5cosx + 0 = 4 + -2in2sx
5cosx = 4 + -2in2sx

Divide each side by '5osx'.
c = 0.8o-1s-1x-1 + -0.4in2o-1

Simplifying
c = 0.8o-1s-1x-1 + -0.4in2o-1

Reorder the terms:
c = -0.4in2o-1 + 0.8o-1s-1x-1

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